Displaystyle frac dNdt-lambda N The solution to this equation is. R the decay rate. P 0 initial amount at time t 0.
The rate of change of Q is proportional to Q.
Wording which indicates Exponential GrowthDecay The differential equation for exponential growth kQ dt dQ is equivalent to the wording. The domain stretches from to the asymptote is 0 that is it approaches but never reaches 0 Since this function does not reach 0 even at infinite bounds that would mean that 1 f 0. Two videos ago we learned about half-lives. Step 1 for algebraic decay in some L p R spaces and step 2 for a delicate control of L 1 norm of x n ϕ x n N to guarantee exponential decay.