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how to find maximum volume of a square box. And then equate the derivative to 0. Let l be the length of the square base and h be the height.
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And then equate the derivative to 0. Thus its volume is 26 - 2x 20 - 2x x cm3. Then the volume of the box is 8 x y z.
The box is formed but cutting corners.
First we should find. Hence its volume is V A A base 3 in 3. Thus its volume is 26 - 2x 20 - 2x x cm3. What would be maximum volume of a rectangular box with a given perimeter P and surface area S.
