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how to find slope of parametric equations. Consider a line passing through the point A x1 y1 and making an angle th with the positive x-axis in anticlockwise direction. This looks similar to what we used while deriving the point-slope form of the equation.
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1 When t0 the point is 62. But we actually want to do some calculus in particular we wanna find the derivative we wanna find the derivative of y with respect to x the derivative of y with respect to x when t when t is equal to negative one third. This is a valid way for parametric equations endgroup lab bhattacharjee Dec 6 13 at 419 begingroup My only other question just to make sure I am doing it.
Hence 1t is the slope of tangent at point P t.
Use t as the parametrized variable 6 2. Consider the plane curve defined by the parametric equations beginalign xt 2t3 labeleq1 yt 3t4 labeleq2 endalign within 2t3. 0 t 5 4 t 3 t 3 t 2 4 t 0 2 4 t 2 t 2 0 t 5 4 t 3 t 3 t 2 4 t 0 2 4 t 2 t 2. One caution when eliminating the parameter the domain of the resulting rectangular equation may need to be adjusted to agree with the domain of the parameter as given in the parametric equations.
