Then I multiply across the rows from the right to the left in order to fill in the I column. Find the actual and approximate time from June 25 2008 to Nov 18. At the end of 2 years P dollars invested at an interest r compounded annually increases to an amount A dollars given by A P1 r 2.
To find the solution I would solve for the value of x.
In fact at 10 interest 200 now is the same as 220 next year. In the formula A represents the final amount in the account that starts with an initial principal P using interest rate r for t years. Then I multiply across the rows from the right to the left in order to fill in the I column. Your 200 now can become 220 in a years time.