Your teachers iterative method which sounds a lot like a bisection method is one approach. Parnovsky in his article url httpinfoifpaneduplfirststepaw-worksfsVparnovskyparnovskypdf and found this differential equation. Look for a solution pair xy that meets both conditions.
Solve the system of simultaneous transcendental equations ex lny 2.
Solve the system of simultaneous transcendental equations ex lny 2. Y 2 1 2 v y 2 log. B K0-1 Lt For the second step and for all the next steps I have to calculate B as. F k v v C 1 y 2.