Point P has the value P. Substitute 1 and 2 into 3 to give 3 in parametric form. In this video I introduce you to what parametric equation is and how to graph it.
Ey L r uP 6 EtP 7 F st P Ey L r tP 7 EuP 6 F st P Ey L r 1 mark Using the factor theorem we know that P Fs is factor of 4.
Doing this gives 1 4 t 2 t 2 2 t 1 t 1 2 double root t 1 2 1 4 t 2 t 2 2 t 1 t 1 2 double root t 1 2. A x t. They can look quite simple like x25 or they can look a little more complicated. 2 f x t2 1.